Mar.12.2011 at 09:44:43 AM
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Problem "Question 1" (0)
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Mar.11.2011 at 09:09:58 PM
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Problem "Symmetric matrix" (0)
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imesecan
Mar.09.2011 at 06:19:36 PM
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Problem "Largest power of two" (2)
| 2 posts |
| Post is deleted
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Mar.07.2011 at 03:06:45 PM
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Problem "Sum of the numbers" (0)
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Mar.07.2011 at 03:06:44 PM
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Problem "Number of Perfect numbers" (0)
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imesecan
Feb.26.2011 at 10:21:20 PM
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Problem "Счастливые билеты" (4)
| 4 posts |
| Post is deleted
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imesecan
Feb.21.2011 at 10:21:27 PM
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Problem "Ladders" (4)
| 4 posts |
| Post is deleted
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imesecan
Mar.04.2011 at 05:51:34 PM
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Problem "Простые числа" (2)
| 2 posts |
| Post is deleted
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imesecan
Feb.26.2011 at 09:56:33 PM
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Problem "Степень" (2)
| 2 posts |
| Post is deleted
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imesecan
Feb.26.2011 at 09:53:47 PM
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Problem "Timer" (2)
| 2 posts |
| Post is deleted
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imesecan
Feb.26.2011 at 10:02:58 PM
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Problem "Коррекция кода" (1)
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| Post is deleted
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imesecan
Feb.24.2011 at 07:07:49 PM
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Problem "The largest product" (3)
| 3 posts |
| Post is deleted
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imesecan
Feb.23.2011 at 09:42:58 PM
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Problem "Triangle" (2)
| 2 posts |
| Post is deleted
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imesecan
Feb.13.2011 at 10:55:31 AM
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Problem "The sum of digits" (4)
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| The question doesn't mention the number of digits. So, the number can have 4 or five digits or 10 digits.
As far as the number has digits we take the digits one by one; and then calculate the sum.
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imesecan
Feb.07.2011 at 09:20:29 PM
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Problem "A+B" (5)
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| In questions when it specifies a condition for sure it's better to check for it. But usually, you shouldn't give extra information like:
cout<<"the sum is"<<A+B<<endl;
but simply say
cout<<A+B;
Just what it asks.
Or, when getting information, you don't say,
cout<<"Enter a number..:";
cin>>A;
but simply say
cin>>A;
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imesecan
Feb.20.2011 at 03:09:01 PM
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Problem "Arithmetic expression" (3)
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| Post is deleted
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imesecan
Feb.20.2011 at 02:21:13 PM
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Problem "Greatest common divisor" (1)
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| int x,y,rem=0;
cin>>x>>y;
// After you read x and y you must make sure that
// x is greater than y. Did you check for this ? :)
while (y!=0)
{
rem=x%y;
y=x; // I think this has to be reverse x=y;
y=rem;
}
// When you quit from the loop y is already 0; Are you sure to show this 0?
cout<<y;
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imesecan
Feb.13.2011 at 01:12:06 AM
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Power of two (2)
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| Post is deleted
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imesecan
Feb.17.2011 at 05:26:04 AM
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Problem "The sum of digits" (1) (1)
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| Post is deleted
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