Time limit 2000/4000/4000/4000 ms. Memory limit 65000/65000/65000/65000 Kb.
Sum of numbers over the average
Count and calculate the sum of numbers which are greater than the average.
You will be first given one number (n) which is followed by a series of integers (n space-separated positive values). Count the numbers and calculate the sum of those numbers as far as the numbers in the series are greater than the average.
Input specification You will be given one integers (n) in the first line, and 1 ≤ n ≤ 10.000. The second line contains a series of integer numbers a[n] where 0 < a[n] ≤ 10. Output specification You will give three numbers, the average (with 2 digits after the floating point number), cnt and sum as integer, where avg is the average of all numbers; cnt is the number of numbers which are greater than the average; and sum is the sum of those numbers. Clearly, if there is no number satisfying the given condition, cnt and sum will have the values 0 (zero).
Sample Input I 5 5 8 4 9 3 |
Sample Input II 7 4 10 8 5 8 9 7
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Sample Output I 5.80 2 17 |
Sample Output II 7.29 4 35
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Explanation of the Output 1: The average si 5.80 and there are two numbers greater than 5.80 and their sum is 17. Для отправки решений необходимо выполнить вход.
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