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Лимит времени 2000/4000/4000/4000 мс. Лимит памяти 65000/65000/65000/65000 Кб. bfs. Plane SegmentationQuestion: The plane equation in three dimensional space can be defined as: ax + by +cz + d=0 Where a, b and c are plane parameters and d is distance of plane from the origin. A point lies on plane if ax + by +cz + d=0 Write a program which counts how many of this points lie on the plane. Input Specifications: In the first line you will be given 4 coefficients of the plane (a, b, c, d) than in the following three lines x, y, z coordinates of four points. where -20000<=a,b,c<=20000, -18000000<=d<=18000000, and -100<=x,y,z<=100 . Output Specifications: Show how many points lie on the plane.
Sample Input II Explanation: Based on plane equation we check if the points lie on plane or not. Check Point 1 equation= ax + by +cz + d=1*2 + 2*2 + 2*6 + (-18)=2+4+12-18=0 Check Point 2 equation= ax + by +cz + d=2*5 + 2*1 + 2*5 + (-18)=10+2+5-18=4 Check Point 2 equation= ax + by +cz + d=2*3 + 2*2 + 2*4 + (-18)=6+4+8-18=0 Total number of points lying on plane is 2 |