ГлавнаяСборникиТурнирыРазделыФорумыУчастникиПечатьПомощьО системе

Разделы > Linear Data Structures: Arrays > задача:


51043 - Genome Sequencing

Гость
• Вопросы к жюри (5)

Задачи раздела

• 51111 - Even Numbers
• 51115 - Pascal Triangle
• 51116 - The Star Triangle
• 51043 - Genome Sequencing
• 51042 - The most frequent k-mer
• 51165 Question 1
• 51171 Question 3
• 51175 Question 2
• 51093 - rgb2gray
• 51092 - Even and Odd
• 51095 - Normal and Trace
• 50382 - Parkside's Other Triangle

Обратная связь

Если у вас есть предложения или пожелания по работе Contester, посетите форум сайта www.contester.ru.

Лимит времени 2000/4000/4000/4000 мс. Лимит памяти 65000/65000/65000/65000 Кб.

Genome Sequencing

Adapted from Genome sequencing by Phillip E. C. Compeau, and prepared by Ibrahim Mesecan
You are working on a genome project. Gene sequences use nucleic acid sequences from the composition: GACT. You are given a genome fragments, and you are asked to merge them. Gene fragments are merged in such a way that, if the last m nucleic acid sequences of gene fragment A matches with the first m nucleic acid sequence of B. These gene fragments A and B can be merged. For example, if m is 2 and you are given TAA as starting gene then you are also given the following nucleic acid sequences: ATG, TGC, TGC, AAACT, AAT and CCG. TAA can be merged with AAT and form TAAT. TAAT is ending with AT and thus it can be merged with ATG and form the sequence TAATG. Then similarly, TAATGC can be formed.

Question: Write a program that reads n gene fragments and after sorting gene fragments, using Sequential search on the sorted list finds the matching sequence. By adding the sequences one after another forms the longest DNA sequence.

Input specification: You will be two integers in the beginning,

  • number of gene fragments (n): an integer between 1 and 10,000,
  • the number nucleic acids used in merge process (m): an integer between 1 and 20
Then, each of the following n lines will have gene fragments where gene fragments contain only the letters (G, A, C or T) and are not longer than 100 letters. The first sequence is the starting sequence and 0 ≤ n ≤ 10,000.

Output specification: Show the fragment which was formed.

Sample Input
7 2
TAA ATG ATG TGC AAACT AAT CTG
Sample Output I
TAAACTGC

Explanation: TAA is the starting DNA fragment, ending with AA. There are two gene fragments starting with AA: AAACT and AAT. Using Sequential search AAACT has been selected as the second gene fragment. Now the new gene fragment is TAAACT, ending with CT. There is only one gene fragment starting with CT: CTG. So, the new gene TAAACTG and it is merged with TGC.



Для отправки решений необходимо выполнить вход.

www.contester.ru