HW_CEN109_2018 |
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Лимит времени 2000/4000/4000/4000 мс. Лимит памяти 65000/65000/65000/65000 Кб.
51205 ECE - Question 1
You work for a company which mainly trades with 3 other
companies. You record your balance in a file (you can
still use cin or scanf to read or if you want you can
read from "input.txt" file) with
the following convention:
- Debit of Company A
- Credit of Company A
- Debit of Company B
- Credit of Company B
- Debit of Company C
- Credit of Company C
Question: Write a program that is going
to read debit/credit information for 3 companies.
Then, it will find out for the following:
- Total debts,
- Total credits
- The most debited company according
to the balance
Input specification
You will be given an integer (n) the number of transactions
where 0 ≤ n ≤ 2000. Then, in each of the following n
lines you will be given 2 numbers :
- Operation Code: an integer from 1 to 6
(where 1 means Debit of Company A, etc.)
- The amount: a floating point number which is
between 0 and one million
Output specification
Show the following information (floating point
numbers with 2 digits precision):
- Total debts,
- Total credits
- The most debited company: a char of (A or B or C)
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Sample Input I
6
2 59
6 154
2 187
5 497
5 31.5
3 488
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Sample Output I
1016.5 400 B
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Explanation:
The balance according to given information is:
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Company |
Total |
Balance |
A |
Debit |
0 |
246 |
Credit |
246 |
B |
Debit |
488 |
-488 |
Credit |
0 |
C |
Debit |
528.5 |
-374.5 |
Credit |
154 |
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Then, the most debited company is B.
Для отправки решений необходимо выполнить вход.
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